Question
How much ice initially at -4 °C is needed to cool down 250 g of water at 80 °C to 0°C?
Take the specific heat capacity of ice to be 2060 J kg-1°C-1
Take the specific heat capacity of ice to be 2060 J kg-1°C-1
Answers
Anonymous
ambiguous...
more ice...none of which melts
OR
less ice...all of which melts
OR
some ice...which partially melts
more ice...none of which melts
OR
less ice...all of which melts
OR
some ice...which partially melts
Anonymous
but they want exactly just enough.
Heat in = heat to raise ice to 0 from -4 (specific heat of ice * ice mass * 4) + heat to melt ice (heat of fusion of water * ice mass)
=
Heat out = specific heat water * 80 * mass of water
Heat in = heat to raise ice to 0 from -4 (specific heat of ice * ice mass * 4) + heat to melt ice (heat of fusion of water * ice mass)
=
Heat out = specific heat water * 80 * mass of water