f(-4) = -131
f(-2) = 7
IVT says that f(x) assumes every value between -131 and 7 on [-4,-2]. In particular, there is some c in [-4,-2] where f(x) = 0.
Use the intermediate value theorem to show that the polynomial function has a zero in the given interval.
f(x)=4x^3+6x^2-7x+1; [-4,-2]
f(-4)=
1 answer
1 answer