Asked by ash
use the intermediate value theorem to show the polynominal function has a zero in the given interval
f(x)=x^5-x^4+3x^3-2x^2-11x+6; [1.5,1.9]
x= -2.33
y=10.19
after i plugged in the 1.5 and 1.9 i just want to know if my x and y are correct
f(x)=x^5-x^4+3x^3-2x^2-11x+6; [1.5,1.9]
x= -2.33
y=10.19
after i plugged in the 1.5 and 1.9 i just want to know if my x and y are correct
Answers
Answered by
ash
i changed it too
f(1.9)= 10.186
f(1.5)= -2.344
f(1.9)= 10.186
f(1.5)= -2.344
Answered by
Steve
so, the IVT says that if f(x) is continuous, it must take on all values between 10.186 and -2.344.
That includes 0, so there is the proof.
BTW, you values for f are correct.
That includes 0, so there is the proof.
BTW, you values for f are correct.
Answered by
ash
so i am right? x and y?
x=-2.344
y=10.186
it was continuous, but they wanted it rounded to three decimal places
x=-2.344
y=10.186
it was continuous, but they wanted it rounded to three decimal places
Answered by
Steve
I wouldn't call your values x and y.
You have two x-values: 1.5 and 1.9
and two values for f(x) or y: -2.344 and 10.186
and, as I said, given those two values for x, your two y values are correct to 3 places.
You have two x-values: 1.5 and 1.9
and two values for f(x) or y: -2.344 and 10.186
and, as I said, given those two values for x, your two y values are correct to 3 places.