Asked by G
                I am trying to solve the sytems of equations using the elimination method.
2x+4y=10
-3x+3y=-6
I tied multiplying the first equation by 2 and the second by 4. Then I tried multiplying the first equation by -3 and the secondy by 3.
The book says the answers are 3,1.
I am not getting these answers.
            
        2x+4y=10
-3x+3y=-6
I tied multiplying the first equation by 2 and the second by 4. Then I tried multiplying the first equation by -3 and the secondy by 3.
The book says the answers are 3,1.
I am not getting these answers.
Answers
                    Answered by
            Jake1214
            
    Try to multiply first equation by 3 and second equation by 2.  You will end up with 6x and -6x, you can eliminate those and then use the substitution method to find y.
    
                    Answered by
            bobpursley
            
    Multiply the second equation by 2/3
2x+4y=10
-2x+2y=-4
add the equations
6y=6
y=1
Put that y back into either equation, and solve for x.
    
2x+4y=10
-2x+2y=-4
add the equations
6y=6
y=1
Put that y back into either equation, and solve for x.
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