Question

• A car moves 26 km due east then 14 km due north. It then turns along a path running north-west with 15 km, then 17 km due west. If the time for the entire journey is 2 hrs.
• Find;
• (a) the car’s average speed in m/s
• (b) the car’s average velocity in km/h

Answer 1

Average speed = (26+14+15+17)/2 km/h
=36 km/h
=36x1000/(60x60) m/s
=10 m/s

Answer 2

(a) For the average speed, divide the total distance travelled, in ANY direction, by 2 hours. That would result in:
(26 + 14 + 15 + 17)/2 = 36 km/h = 36000 m/3600 s = 10.0 m/s

(b) For the average velocity, divide the distance between the starting and finishing points (a vector sum) by 2 hours.
The vector velocity from start to finish is
(26i + 14j -10.607i + 10.607j -17i)/2
= (1.607i -24.607j)/2
(i represents the east direction and j represents the north direction)
= 0.803 i -12.304 j

The magnitude of the average velocity (average speed) is 12.33 km/h, and the direction is slightly north of west.

Answer 3

Simple question
:D