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black_widow
Questions (14)
How to compare the melting point of two ionic bod or two covalent bond?
0 answers
921 views
why does MgO has a higher boiling and melting point than NaCl?
0 answers
593 views
What is the difference between e/z notation and cis-trans isomerism?
4 answers
521 views
What is Mersenne prime?
1 answer
337 views
Solve the inequality //(2x-1)(x+3)/-4/< 1
where /x/ is the modulus of x.
0 answers
300 views
Is every Fermat number 2^(2^n) + 1 composite for n > 4?
0 answers
321 views
Solve the inequality //(2x-1)(x+3)/-4/< 1
where /x/ is the modulus of x.
2 answers
310 views
If G is a group of order 12, the G must have a subgroup of all of the following orders EXCEPT
Choose one answer. a. 0 b. 12 c. 2
1 answer
1,171 views
Let the bottom edge of a rectangular mirror on a vertical wall be parallel to and h feet above the level floor. If a person with
1 answer
1,057 views
What is the value of e^i(pi)?
where i^2 =-1 ,e =exponential
1 answer
874 views
Prove : (a^2+b^2+c^2+d^2)(1/a^2+1/b^2+1/c^2+1/d^2)greater equal to 16
1 answer
323 views
Prove : (a^2+b^2+c^2+d^2)(1/a^2+1/b^2+1/c^2+1/d^2)greater equal to 16
0 answers
292 views
Given that a,b,c >0
Prove : (a/b + b/c +c/a)(b/a +c/b +a/c)>0
1 answer
298 views
Is pore protein = channel protein?
1 answer
334 views
Answers (33)
by using long division, divide x^4-6x^3+16x^2-25x+10with x^2-2x+k, then you will find: remainder=(-9+2k)x +10-8k+k^2 comparing with x + a, -9+2k=1,k=5 a=10-8k+k^2,a=-5 therefore k + a=5-5=0
is it 3?
is this mean that e/z notation can definitely explain cis-trans isomerism but cis-trans not necessary can explain e/z notation ?
i have seen it but still don't understand.....
sorry about that.... I thought 0 is neither even nor odd....
Is it correct?
My way of solving...... Let k=m+1 2^(m+1)-2^m
Let a>b a=2n+1+2k ,n,k is positive b=2n+1 (a+b)/2=2n+1+k (a-b)/2=k If k is odd, then (a+b)/2 is even (a-b)/2 is odd If k is even, (a+b)/2 is odd (a-b)/2 is even The same method also applies if a
let x^(1/3)=a 6a^2-11a+4=0 a=0.5, a=4/3 x=1/8, x=64/27
My answer is 440 My way of solving: xyz(z)=−64y−128x (1) xyz(x)=−32y−32z (2) 3xyz(y)=128x−64z (3) (1)-(2) xyz(z-2x)=64(z-2x) xyz=64 ,z=2x if z=2x,x=y=z=0 if xyz=64, sub xyz=64 into (1),(2),(3) simplify it and you can get: z=-y-2x (4) 2x=-y-z (5)
f(x)=3x^2-21x+36 sum of roots =-(-21/3)=7
sorry the answer should be 101 I do like this: first consider the possible last digit of the number, then you have 0,1,5,6 Let N be ab For number end with 0, the last two digits of N will be 00 no numbers can be formed as 00 is not a 2 digit numbers For
the answer is 76
The pull of cable is 5.24x10^3N The force exerted by the man =75N Is it correct?
Let length of AB =a sABC=sABD+sACD (s stands for area) 1/2x60x(a^2-30^2)^0.5=1/2x(16a+32a) 5(a^2-30^2)^0.5=4a 25a^2-16a^2=25x30^2 a^2=2500 a=50
AB=50
Given f(x)=2x^3-10x^2+11x+12 f(3)=2(3)^3-10(3)^2+11(3)+12 = 9 because f(3)not equal to 0 Therefore x-3 is not a factor of f(x)
the range of x is x>4
1/a + 1/b + 1/c = 0 bc+ac+ab = 0 a^2 + b^2 + c^2 =(a+b+c)^2 -2(ab+bc+ac) =(11)^2-2(0) =121
x^2(8+x)(x-9)/(x+4)(x-7) >=0 x^2(8+x)(x-9)(x+4)(x-7)>=0 therefore the ranges are x>=9,0
still cant solve it.....
Average speed = (26+14+15+17)/2 km/h =36 km/h =36x1000/(60x60) m/s =10 m/s
opps sorry made some calculation mistakes....
it should be x>-3
Yes the magnitude will be the same until the force exceed the maximum frictional force then the system will only move with an acceleration.
Is the answer is 170m/s?
Consider only vertical component (because the object does not move horizontally) Use formula v=u+at v=0+9.8(7) v=68.6m/s
Impulse = change in momentum I= m(v-u) I=70.5 (5.85-0) I=412.4Ns
is it x^3 -(2x+5)/(x+4) ?
Is your question is f(x)= x^3-2x+(5/x)+4 ?
Let the magnitude of friction force = f acceleration ,a = 0 (because it moves with constant speed) F=ma 20-f=30x0 f=20N
Let the resistive force = f F=ma 10-f=0.2x2 f=9.6N
Let 25x^2+(a−15)x+9=0 Discriminant B^2-4AC=0 (only one distinct root) (a-15)^2-4(25)(9)=0 (a-15)^2=900 a=15+30 or a=15-30 a=45 a=-15 therefore sum of a =45+(-15) a =30
