If 180<A<270 and sinA= -ã(5)/3, find tan(1/2)A.

prove that sinA-cosA+1/sinA+cosA-1=1/secA-tanA

Prove : (sinA-cosA+1)/(sinA+cosA-1) = (1+sinA)/cosA

If (cosa-sina)/sina = 2 , then what is tga = ?

tanA+sinA=p, tanA-sinA=q shows that p^2+q^2

SinA+ cosA=17/3 find sinA-cosA

SinA + sinB/sinA - sinB= tanA+B/2cotA-B/2

Cos^2A/sinA-cosecA+sinA=0 Prove lHS =RHS

If sinA=3/5 when pi/2 < A < pi and cosB=5/13 when 3pi/2 < B < 2pi, find the exact value of the funct...

1+(sinA/tanB)^2/1+(sinA/tanC)^2

Asked by Joseph79