59.0 mL of a 1.80 M solution is diluted to a total volume of 268 mL. A 134-mL portion of that solution is diluted by adding 171 mL of water. What is the final concentration? Assume the volumes are additive.

Answer 1

1.80*(59/268)=concentration

concentration*(134/171)= concentration 2

Answer 2

almost
1.80M x (59.0 mL/268 mL) = about 0.4 but that is not exact.

Then 0.4 x [134 mL/(134 mL + 171 mL)]

Answer 3

Read it halfway; I thought it was going to say making a solution to 171mL using 134mL of the previous. Dr. Bob222 is correct.