Asked by Chelsea

51.0 mL of a 1.20 M solution is diluted to a total volume of 248 mL. A 124-mL portion of that solution is diluted by adding 125 mL of water. What is the final concentration? Assume the volumes are additive.

Answers

Answered by DrBob222
How many mols did you start with? That's M x L = 1.20 x 0.051 = 0.0612 and that is in 248 so the concn of the first solution is 0.0612/0.248 = about 0.25 but you should redo it for more accuracy.
Then 124 mL of that is diluted.
New concn is about 0.25 x [(124/(124+125)] = ?
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