Asked by Maura

If a snowball melts so that its surface area decreases at a rate of 4 cm2/min, find the rate at which the diameter decreases when the diameter is 12 cm.
Answered by Steve
a = 4 pi r^2 = pi d^2
da/dt = 2 pi d dd/dt
Now just solve
-4 = 2 pi (12) dd/dt
Answered by Deep
-1/12pi
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