Asked by Grecia
A snowball melts in such a way that its diameter is constantly decreasing at a rate of 0.3
cm/min Find the rate of change of the area at the time the radius is 5 cm.
cm/min Find the rate of change of the area at the time the radius is 5 cm.
Answers
Answered by
mathhelper
given:
d(diameter)/dt = .3 cm/min
or
d(radius) = ..15 cm/min
Assuming that by area you mean surface area ....
Surface Area = SA
SA = 4π r^2
d(SA)/dt = 8π r dr/dt
d(SA) = 8π(5)(.15)
= 6π cm^2/min
d(diameter)/dt = .3 cm/min
or
d(radius) = ..15 cm/min
Assuming that by area you mean surface area ....
Surface Area = SA
SA = 4π r^2
d(SA)/dt = 8π r dr/dt
d(SA) = 8π(5)(.15)
= 6π cm^2/min
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.