Asked by Anonymous
A snowball melts at a rate of 2 cubic inch an hour. When the volume is 36π in^3, how fast is the radius shrinking? V=(4/3)(pi)(r^3)
Answers
Answered by
Steve
well, you have the formula
v = 4/3 pi r^3
dv/dt = 4pi r^2 dr/dt
Now just find r from v, and you know that dv/dt = -2, so solve for dr/dt
v = 4/3 pi r^3
dv/dt = 4pi r^2 dr/dt
Now just find r from v, and you know that dv/dt = -2, so solve for dr/dt
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