Question
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
Answers
bobpursley
Assuming the digits are from 1 to 9, then the even is 2,4,6,8 and the odd are 1,3,5,7,9.
Prodd(ways/choices)=5/(2+5)
Prodd(ways/choices)=5/(2+5)
lily
how do you do probability in decimals
Ty'johnna
ex. 3 and 4 chance of something, it would be .75 because 4 (100) x 3 of 100 is 75 so its .75!
eric
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even
derek
A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3?
Sophia
I'm sorry but i don't know the answer to your question, but i need help on this question:
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
Sophia
I think the answer is 2/7