Asked by Brooke
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
Answers
Answered by
bobpursley
Assuming the digits are from 1 to 9, then the even is 2,4,6,8 and the odd are 1,3,5,7,9.
Prodd(ways/choices)=5/(2+5)
Prodd(ways/choices)=5/(2+5)
Answered by
lily
how do you do probability in decimals
Answered by
Ty'johnna
ex. 3 and 4 chance of something, it would be .75 because 4 (100) x 3 of 100 is 75 so its .75!
Answered by
eric
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even
Answered by
derek
A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3?
Answered by
Sophia
I'm sorry but i don't know the answer to your question, but i need help on this question:
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
A locker combination has three nonzero digits, and digits cannot be repeated. If the first two digits are even, what is the probability that the third digit is even?
Answered by
Sophia
I think the answer is 2/7
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