1. Since you can repeat digits, your second choice will be independent of your first
You can't have a zero, so that leaves 9 to choose from, one of which must be the "8"
prob(of the 8) = ...
2. Well, the first digit could be 1, 2, or 3
How many cases is that?
How many digits were available to you?
1. A locker combination has two nonzero digits, and digits can be used twice. The first number is 8. What is the probability that the second number is 8?
2. My locker combination has three digits. None of the digits are zero. What is the probability that the first digit of my locker combination is less than 4?
I dont expect the answer, i just need help figuring out how to solve it
1 answer