Asked by Melissa

A test charge of +3.00 10-6 C experiences a downward electrostatic force of 11 N when placed at a certain point in space. What are the magnitude and direction of the electric field at this point?

Answers

Answered by drwls
The field direction is down and the field strength is 11/3*10^-6 = 3.7*10^6 N/C (or volts/meter)

This is close to the field strength that casues air breakdoown.
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