forc=Kq2*q0/.03^2
solve for q2
q2=force*.03^2/kq0
c is asking for charge from force
When a test charge q0 = 9 nC is placed at the origin, it experiences a force of 8 times 10-4 N in the positive y direction.
(c) If this force is due to a charge on the y axis at y = 3 cm, what is the value of that charge?
so in a I found E to be 88888.889
in b I found the F on a charge of -4nC to be -3.555e-4
I thought for C I would just use E=kq/(r^2) but it was wrong
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