Asked by Anonymous
Calculate a person's hang time if he moves horizontally 2 m during a 1.39 m high-jump.
Answers
Answered by
drwls
To go up and down H = 1.39 meters requires
2*sqrt(2H/g)= 1.07 seconds
regardless of how far the jumper moves horizontally. They provided the 2 meter distance to trick you.
2*sqrt(2H/g)= 1.07 seconds
regardless of how far the jumper moves horizontally. They provided the 2 meter distance to trick you.
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