Asked by lISA

IF HANG TIME FOR A SHOT BY A PROFESSIONAL BASKETBALL PLAYER IS O.85 SECONDS WHAT IS THE VERTICAL DISTANCE OF THE JUMP ROUNDED TO THE NEAREST TENTH OF A FOOT?

Answers

Answered by Damon
falls for .85/2 = .425 second

h = (1/2) g t^2 = (1/2)(32)(.425^2)
= 2.89 ft = 2.9 ft
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