IF HANG TIME FOR A SHOT BY A PROFESSIONAL BASKETBALL PLAYER IS O.85 SECONDS WHAT IS THE VERTICAL DISTANCE OF THE JUMP ROUNDED TO THE NEAREST TENTH OF A FOOT?

Answer 1

falls for .85/2 = .425 second

h = (1/2) g t^2 = (1/2)(32)(.425^2)
= 2.89 ft = 2.9 ft