Question
IF HANG TIME FOR A SHOT BY A PROFESSIONAL BASKETBALL PLAYER IS O.85 SECONDS WHAT IS THE VERTICAL DISTANCE OF THE JUMP ROUNDED TO THE NEAREST TENTH OF A FOOT?
Answers
Damon
falls for .85/2 = .425 second
h = (1/2) g t^2 = (1/2)(32)(.425^2)
= 2.89 ft = 2.9 ft
h = (1/2) g t^2 = (1/2)(32)(.425^2)
= 2.89 ft = 2.9 ft