Asked by Lisa
the general "hang time" of a punt is measured to be 4.5sec. if the ball was kicked @ an angle of 63deg. above the horizontal & was caught @ the same level from which it was kicked, what was its initial speed?
Answers
Answered by
Damon
time to top = 4.5/2 = 2.25 seconds
vertical velocity v = Vo + a t
at top v = 0
0 = Vo - 9.8 (time to top)
Vo = 9.8 (2.25)
Vo = 22.05
sin 63 = 22.05/speed
speed = 22.05/ .891
=24.7
vertical velocity v = Vo + a t
at top v = 0
0 = Vo - 9.8 (time to top)
Vo = 9.8 (2.25)
Vo = 22.05
sin 63 = 22.05/speed
speed = 22.05/ .891
=24.7
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.