Question

A particle is moving clockwise around a circle with a radius 3.31 m. The magnitude of the total acceleration of the particle at the given instant is 14.3 m/s^2; the angle between the vector of total acceleration and the radius-vector of the particle is 30◦.
Find the centripetal acceleration, tangential acceleration and speed of the particle at the given instant.

Answer 1

a(centr) = a•cosα=14.3•cos30=…
a(tang)=a•sinα=14.3•sin30=…
a(centr)= v²/R,
v=sqrt{a(centr) •R}=...

Answer 2

Thank you!