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A particle is moving clockwise in a circle of radius 1.75 m. At a certain instant, the magnitude of its acceleration is
a =

a

= 39.0 m/s2,
and the acceleration vector has an angle of θ = 50° with the position vector, as shown in the figure. At this instant, find the speed,
v =

v

,
of this particle.

Answers

v= sqrt (a*r*cos 50)
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