Question

a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its x-coordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?
bobpursley
distance to origin=sqrt(x+ x^2)

d distance/dt= 1/(2sqrt(x+x^2)*(dx/dt+ 2xdx/dt)

you have x, dx/dt solve for ddistance/dt

Related Questions

A particle is moving along the curve y= 3 \sqrt{3 x + 4}. As the particle passes through the point (... A particle is moving along the x-axis so that at time t its acceleration is a(t)=ðcos(ðt) At time... A particle is moving along a horizontal straight line. The graph of the position function (the dista... A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)In(2t). Fin... A particle is moving along the x-axis so that its position at t>=0 is given by s(t)=(t)ln(5t). Find... A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 5t + 3,... An 80g particle moving with an initial velocity of (50m/s)î strikes and sticks to a 60g particle mo... 1 A particle is moving in a stright line with the position at any time t is given by s= t³–9t²+3t+1,... A particle is moving as given by the data below 4sin(t)-3cos(t); s(0)=0