Asked by jackie
a particle is moving along the cure y=sqrt x. as the particle passes through the point (4,2), its x-coordinate increase at a rate of 3 cm/s. how fast is the distancefrom the particle to the origin changing at this instant?
Answers
Answered by
bobpursley
distance to origin=sqrt(x+ x^2)
d distance/dt= 1/(2sqrt(x+x^2)*(dx/dt+ 2xdx/dt)
you have x, dx/dt solve for ddistance/dt
d distance/dt= 1/(2sqrt(x+x^2)*(dx/dt+ 2xdx/dt)
you have x, dx/dt solve for ddistance/dt
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.