Question

For the reaction
? FeCl2 + ? Na3PO4 → ? Fe3(PO4)2 + ? NaCl
what is the maximum mass of Fe3(PO4)2 that
could be formed from 5.25 g of FeCl2 and
1.62 g of Na3PO4?
Answer in units of g

Answer 1

This is a limiting reagent problem; I know that because amounts are given for BOTH reactants.
6FeCl2 + 4Na3PO4 → 2Fe3(PO4)2 + 12NaCl

mols FeCl2 = grams/molar mass.
mols Na3PO4 = grams/molar mass

Convert mols FeCl2 to mols Fe3(PO4)2 using the coefficients in the balanced equation.
Convert mols Na3PO4 to mols Fe3(PO4)2.
It is likely these two values will be different which means one of them is wrong. The correct value in limiting reagent problems is ALWAYS the smaller value and the reagent responsible for producing that number is the limiting reagent.
Use the smaller value and convert to grams. g = mols x molar mass.

Answer 2

Na cl