Question

For the reaction
3 FeCl2 + 2 Na3PO4 → Fe3(PO4)2 + 6 NaCl ,
what is the maximum amount of Fe3(PO4)2
which could be formed from 11.26 g of FeCl2
and 13.34 g of Na3PO4?

Answer 1

This is a limiting reagent problem. You know that because amounts are given for BOTH reactants.
Convert 11.26 g FeCl2 to mols. mols = g/molar mass. Approximately 0.09

Convert 13.34g Na3PO4 to mols.
Approximately 0.08

Convert mols FeCl2 to mols of the product using the coefficients in the balanced equation. About 0.09 x 1/3 = about 0.03

Convert mols Na3PO4 to mols of the product. Same procedure. About 0.08 x 1/2 = 0.04.

You will note that you have two values for the product; of course, both can't be right. The correct answer in limiting reagent problems is ALWAYS the smaller value. Make sure to confirm all of the values above because I've estimated them.

Then mols product x molar mass product = grams product.