Asked by Karen
Divide 3n^2-n/n^2-1/n^2/n+1
Answers
Answered by
Damon
You are unlikely to get a reply if you are not clear about what are the various numerators and denominators. Do you mean what you typed or:
(3n^2-n)/(n^2-1)/(n^2)/(n+1 )
(3n^2-n)/(n^2-1)/(n^2)/(n+1 )
Answered by
Damon
If it is as I typed it:
[ (3n^2-n)/(n^2-1) ]/ [(n^2)/(n+1 ) ]
[ (3n^2-n)/{n+1)(n-1) } ]/ [(n^2)/(n+1 ) ]
[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]
[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]
[ (3n-1)/(n-1) } ]/ [(n) ]
(3n-1) / (n^2-n)
[ (3n^2-n)/(n^2-1) ]/ [(n^2)/(n+1 ) ]
[ (3n^2-n)/{n+1)(n-1) } ]/ [(n^2)/(n+1 ) ]
[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]
[ (3n^2-n)/(n-1) } ]/ [(n^2)/ ]
[ (3n-1)/(n-1) } ]/ [(n) ]
(3n-1) / (n^2-n)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.