Question

Please help me

Divide.
(9x^3-10+19+6x^4)/(-2x^2+3x-3)

Write your answer in the form Q(x)+ R(x)/ -2x^2+3x-3,
where Q(x) is the quotient and R(x) is the remainder.

Answer 1

First rearrange and simplify the numerator to:
6x^4 + 9x^3 + 9

Just divide as your would with any long division problem.

If you post your answer I can tell you if you are correct.

Is there something in particular you do not understand?

Answer 2

Just not good at division

Answer 3

I'll try, but the formatting here doesn't allow for easy alignment of columns.

xxxxxxxxxxxxx-3x^2 - 9x - 9
-2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9
------------6x^4 - 9x^3 + 9x^2
subtraction-------18x^3 - 9x^2
------------------18x^3 - 27x^2 + 27x
subtraction-------------18x^2 - 27x + 9
------------------------18x^2-27x + 27
subtractionxxxxxxxxxxxxxxxxxxxxxxx -18

Answer in the form
Q(x)+ R(x)/ -2x^2+3x-3,
-3x^2 - 9x - 9 + -18/(-2x^2 + 3x - 3)

I don't know how you will follow this because of the formatting.

Answer 4

Ok I will try to figure it out and ask if I need anymore questions. thanks for your help

Answer 5

You're welcome and good luck :).