Asked by Karen
Divide 3n^2-n/n^2-1/n^2/n+1
Answers
Answered by
Steve
You must see how confusing your expression is when rendered here.
If you mean
(3n^2-n)/(n^2-1) / n^2/(n+1)
then that is
n(3n-1)/((n-1)(n+1)) * (n+1)/n^2
Now the n and (n+1) factors cancel, and you are left with
(3n-1)/(n-1)
If you mean
(3n^2-n)/(n^2-1) / n^2/(n+1)
then that is
n(3n-1)/((n-1)(n+1)) * (n+1)/n^2
Now the n and (n+1) factors cancel, and you are left with
(3n-1)/(n-1)
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