Asked by hannah
Calculate [OH- ] and pH for each of the following strong base solutions. (Kw = 1.0 10-14.)
3.155 g of KOH in 460.0 mL of solution]
how do you do this
3.155 g of KOH in 460.0 mL of solution]
how do you do this
Answers
Answered by
DrBob222
M = mols/L
You get mols from grams/molar mass.
You get L from 460 mL and convert to L.
(OH^-) = M
pOH = -log(OH^-)
pH + pOH = pKw = 14. You know pOH and pKw, solve for pH.
You get mols from grams/molar mass.
You get L from 460 mL and convert to L.
(OH^-) = M
pOH = -log(OH^-)
pH + pOH = pKw = 14. You know pOH and pKw, solve for pH.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.