Asked by K
Sodium azide (NaN3) yields N2 gas when heated to 300 degrees Celsius , a reaction used in automobile airbags. If 1.00 mol of N2 has a volume of 47.0 liters under the reaction conditions , how many liters of gas can be formed by heating 35g of NaN3?
The reaction is 2Nan3------>3N2(g)+2Na
The reaction is 2Nan3------>3N2(g)+2Na
Answers
Answered by
Devron
35g of NaN3*(1 mole/65.01g of NaN3)= moles of NaN3
moles of NaN3*(3 moles of N2/2 moles of NaN3)=moles of N2
moles of N2*(47 L/1 mole of N2)= volume in L.
moles of NaN3*(3 moles of N2/2 moles of NaN3)=moles of N2
moles of N2*(47 L/1 mole of N2)= volume in L.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.