Question
90g of NaN3 decomposes at stp calculate the concentration of N2 produced
Answers
DrBob222
2NaN3(s)→2Na(s)+3N2(g)
mols NaN3 = grams/molar mass = 90/65 = about 1.4 mols.
Then 1.4 mols NaN3 will give 1.4 x (3 mols N2/2 mols NaN3) = 2.08 moles N2 gas @ STP. What's the concentration. All depends upon the volume you have it confined in. (N2) = moles/L = ?
mols NaN3 = grams/molar mass = 90/65 = about 1.4 mols.
Then 1.4 mols NaN3 will give 1.4 x (3 mols N2/2 mols NaN3) = 2.08 moles N2 gas @ STP. What's the concentration. All depends upon the volume you have it confined in. (N2) = moles/L = ?