Asked by Fatima
90g of NaN3 decomposes at stp calculate the concentration of N2 produced
Answers
Answered by
DrBob222
2NaN3(s)→2Na(s)+3N2(g)
mols NaN3 = grams/molar mass = 90/65 = about 1.4 mols.
Then 1.4 mols NaN3 will give 1.4 x (3 mols N2/2 mols NaN3) = 2.08 moles N2 gas @ STP. What's the concentration. All depends upon the volume you have it confined in. (N2) = moles/L = ?
mols NaN3 = grams/molar mass = 90/65 = about 1.4 mols.
Then 1.4 mols NaN3 will give 1.4 x (3 mols N2/2 mols NaN3) = 2.08 moles N2 gas @ STP. What's the concentration. All depends upon the volume you have it confined in. (N2) = moles/L = ?
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.