Asked by sreedevi

3.14M NaN3 (pKb=9.28) is titrated with .663M HClO4 until it reaches the equivalence point. How do you calculate the pOH at the equivalence point.

I tried and got something around 9 but its not correct i used a table but without liters given i have not idea where to go or what to do. Please help!
Answered by DrBob222
Do you have an equation for the titration?
Answered by sreedevi
H^+ + N3- = HN3
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