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just as with resistors in parallel,
1/C = 1/C1 + 1/C2
1/C = 1/C1 + 1/C2
1/C_total = 1/C1 + 1/C2 + ...
In this case, you have two capacitors connected in series, so the formula becomes:
1/C_total = 1/C1 + 1/C2
Now, substitute the given values:
1/C_total = 1/25 + 1/125
To add these fractions, the denominators must be the same, so we need to find a common denominator:
1/C_total = 5/125 + 1/125
Now add the fractions:
1/C_total = 6/125
To solve for C_total, take the reciprocal of both sides:
C_total = 125/6
Rounding this result to the nearest whole number, the total capacitance is approximately 21 Farads.