Asked by ruth abera
. The effective capacitance of two capacitors, when connected in parallel is 32 μF and when connected in series is 6μF. What are the values of the two capacitors in μF?
Answers
Answered by
R_scott
a + b = 32 ... a = 32 - b
1/a + 1/b = 1/6 ... 6 a + 6 b = a b
substituting ... 192 - 6 b + 6 b = 32 b - b^2 ... b^2 - 32 b + 192 = 0
solve for b ... factoring or quadratic formula
... the two roots are the values for a and b
1/a + 1/b = 1/6 ... 6 a + 6 b = a b
substituting ... 192 - 6 b + 6 b = 32 b - b^2 ... b^2 - 32 b + 192 = 0
solve for b ... factoring or quadratic formula
... the two roots are the values for a and b
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