Asked by Jodie
A capacitor has a capacitance of 55 pF. In the charging process electrons are removed from one ate and placed on the other plate. When the potential difference between the plates is 5.3 v how many electrons have been transferred?
Answers
Answered by
Elena
C=q/U =Ne/U ,
N=CU/e=55•10⁻ ¹²•5.3/1.6•10⁻ ¹⁹ =1.82•10⁹
N=CU/e=55•10⁻ ¹²•5.3/1.6•10⁻ ¹⁹ =1.82•10⁹
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