I=317 A
B=7.69•10⁻³ T
B(wire)=B
B(wire)=μ₀I/2πa =B
a= μ₀I/2πB=
=4π•10⁻⁷•317/2π•7.69•10⁻³=8.24•10⁻³ m
A long, straight wire carrying a current of 317 A is placed in a uniform magnetic field that has a magnitude of 7.69 × 10-3 T. The wire is perpendicular to the field. Find a point in space where the net magnetic field is zero. Locate this point by specifying its perpendicular distance from the wire.
3 answers
IDK THIS IS REALLY HARDD
Clarification to Elena's Answer:
B(wire)=(4π•10⁻⁷•317)/(2π•7.69•10⁻³)=8.24•10⁻³ m
B(wire)=(4π•10⁻⁷•317)/(2π•7.69•10⁻³)=8.24•10⁻³ m
2 answers