In this situation,
F = B I L
where L is the length of the wire.
Therefore,
B = F/(IL)
You got the correct number. The units are Teslas (T)
0.50 m and it experiences a force of 0.90 N while carrying a current of 4.0 A, what is the strength of the magnetic field?
I did the work and got:
0.45 ...???
F = B I L
where L is the length of the wire.
Therefore,
B = F/(IL)
You got the correct number. The units are Teslas (T)
F = BIL
Where:
F is the force on the wire,
B is the magnetic field strength,
I is the current flowing through the wire, and
L is the length of the wire.
In this case, we are given:
F = 0.90 N (force on the wire),
I = 4.0 A (current flowing through the wire), and
L = 0.50 m (length of the wire).
Plugging these values into the formula, we can solve for the magnetic field strength (B):
B = F / (IL)
B = 0.90 N / (4.0 A * 0.50 m)
B = 0.90 N / 2.0 A*m
B = 0.45 T (tesla)
So, the strength of the magnetic field is 0.45 T.
F = BILsinθ
Where:
F = magnetic force on the wire
B = strength of the magnetic field
I = current flowing through the wire
L = length of the wire
θ = angle between the wire and the magnetic field
In this case, the wire is oriented at right angles to the magnetic field, so the angle θ is 90 degrees.
Given:
F = 0.90 N
I = 4.0 A
L = 0.50 m
θ = 90 degrees
Plugging in the values into the formula:
0.90 N = B * 4.0 A * 0.50 m * sin(90 degrees)
Since sin(90 degrees) = 1, we can simplify the equation to:
0.90 N = B * 4.0 A * 0.50 m
Now, solve for B:
B = 0.90 N / (4.0 A * 0.50 m)
B = 0.90 N / 2.0 A*m
B = 0.45 Tesla
So, the strength of the magnetic field is 0.45 Tesla.