Asked by rose
                a sample of glucose, c6h12o6 contains 2.03*10^21 atoms of carbon. 
(a)how many atoms of hydrogen does it contain?
(b)how many molecules of glucose does it contain?
(c)how many moles of glucose does it contain?
(d)what is the mass of this sample in grams?
its kinda long, but i would appreciate it if someone would guide me through it
thank you:)
            
        (a)how many atoms of hydrogen does it contain?
(b)how many molecules of glucose does it contain?
(c)how many moles of glucose does it contain?
(d)what is the mass of this sample in grams?
its kinda long, but i would appreciate it if someone would guide me through it
thank you:)
Answers
                    Answered by
            Devron
            
    Molecular weight of glucose is 180.16 g/mo and its formula is C6H1206.
a.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(12 moles of H/6 moles of C)*(6.02x10^23 atoms/mole of H)=atoms of H
****Notice that Avogadro's number cancels out
b.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(6.02 x 10^23 atoms/1mole of glucose)= molecules of glucose
****Notice that Avogadro's number cancels out
c.)2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)= moles of glucose
d.2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(180.16 g/mole)= glucose in grams
    
a.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(12 moles of H/6 moles of C)*(6.02x10^23 atoms/mole of H)=atoms of H
****Notice that Avogadro's number cancels out
b.) 2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(6.02 x 10^23 atoms/1mole of glucose)= molecules of glucose
****Notice that Avogadro's number cancels out
c.)2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)= moles of glucose
d.2.03 x10^21 atoms of carbon*(1 mol/6.02 x 10^23 atoms)*(1 mole of glucose/12 moles of C)*(180.16 g/mole)= glucose in grams
                    Answered by
            rose
            
    Thank you soooooooooooo much!!!
    
                    Answered by
            Corona
            
    On problem C, why is the mole for Carbon 12 and not 6. Isn't the mole of H 12?
    
                    Answered by
            XXXX
            
    Setup is correct, but in parts b, c, and d, it should be 6 moles of carbon because the formula is C6H12O6, NOT C12H12O6 
    
                    Answered by
            Anonymous
            
    Not sure if I did this right didn’t understand but for
A. I got 5.02 x 100^22
B.6.02x10^23 C.083
D.180.16g
can someone please explain it to me
    
A. I got 5.02 x 100^22
B.6.02x10^23 C.083
D.180.16g
can someone please explain it to me
                    Answered by
            Zach
            
    To make this easier. The ratio of carbon to hydrogen is 1/2 so for part a you have to multiply it by 2 so the answer would be 4.06 x 10^22.
For part b, you would have to find the molar mass of glucose which is 180.16 and multiply it by 6.023 x 10^23 so the answer would be 1.085 x 10^26. For c, you would divide the number found in part b by 6.023 x 10^23, and in part d it is the molar mass of glucose. Hope this helps
    
For part b, you would have to find the molar mass of glucose which is 180.16 and multiply it by 6.023 x 10^23 so the answer would be 1.085 x 10^26. For c, you would divide the number found in part b by 6.023 x 10^23, and in part d it is the molar mass of glucose. Hope this helps
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