Asked by Bliss
use the following data to calculate the mean bond enthalpy values for the C-H and C-C bonds.
CH4(g)-C(g) + 4H(g) standard enthalpy change is +1648 kj/mol
C2H6(g)-2C(g) + 6H(g) standard enthalpy change is +2820 kj/mol
CH4(g)-C(g) + 4H(g) standard enthalpy change is +1648 kj/mol
C2H6(g)-2C(g) + 6H(g) standard enthalpy change is +2820 kj/mol
Answers
Answered by
Banter
412 kj mol^-1 (4 bonds and they're all C-H so it's 1648 /4)
and 2820-(6*412) = 348 kj mol^-1
remember there aren't 2 C-C bonds - just the one!!!
and 2820-(6*412) = 348 kj mol^-1
remember there aren't 2 C-C bonds - just the one!!!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.