Asked by Alisa
Given the following data, calculate the enthalpy change for the reaction
S(s)+ O2(g)->SO2(g)
S(s)+(3/2)O2(g)->SO3(g) H=-395.2 kJ
2SO2(g)+ O2(g)->2SO3(g) H=-198.2 kJ
S(s)+ O2(g)->SO2(g)
S(s)+(3/2)O2(g)->SO3(g) H=-395.2 kJ
2SO2(g)+ O2(g)->2SO3(g) H=-198.2 kJ
Answers
Answered by
DrBob222
deltaHrxn = (n*DH products) - (n*DH reactants)
DH = delta H.
DH = delta H.
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