y= (x^3 - 2sqrx)/(x)

y'=

2 answers

rewrite the square root of x as x^1/2

This is the quotient rule.

demoninator times the derivative of the numerator minus the numerator times the derivative of the denominator all over the denominator squared.

So... We know the derivative will have an x^2 in the denomoniator.

Can you do the top part of the fraction?
who needs the quotient rule?
y = x^2 - 2x^-1/2
y' = 2x + x^-3/2