Question

Quadratic Formula
1.) x+6/x=-7
2.) 4x/x+4 + 3/x-1 = 15/x^2+3x-4
3.) x+3/x - 2/x+3 = 6/x^2+3x

formula:
-B+ sqrt B^2 + (-4)(a)(c)/2a
f u only wanted to use the formula it's not necessary though.

please help me! it's going to pass tomorrow!! please!

Answer 1

your formula should say:
x = (-b ± √(b^2 - 4ac) )/(2a)

1. x + 6/x = -7
each term by x

x^2 + 6 = -7x
x^2 + 7x + 6 = 0
it factors, no need for the formula
(x+1)(x+6) = 0
x = -1 or x = -6

2. you probably meant:
4x/(x+4) + 3/(x-1) = 15/(x^2 + 3x - 4)
4x/(x+4) + 3/(x-1) = 15/((x-1)(x+4) )
multiply each term by (x+4)(x-1) , the LCD
4x(x-1) + 3(x+4) = 15
4x^2 - 4 + 3x + 12 = 15
4x^2 + 3x -7 = 0
x = (-3 ±√(9-4(4)(-7)) )/8
= (-3 ±√121)/8 = (-3 ± 11)/8
x = 1 or x = -7/4

or.... we could have factored it again
(x-1)(4x + 7) = 0
x = 1 or x = -7/4

3. again, brackets will be essential.
(x+3)/x - 2/(x+3) = 6/( x(x+3))
the LCD is x(x+3) , so multiply each term by x(x+3)
You can take it from there.