Asked by Justine
Use the quadratic formula to find the roots of x^2-6x=3
Answers
Answered by
Marth
x^2-6x-3=0
x = (-b +/- sqrt(b^2-4ac))/(2a)
x = (6 +/- sqrt(6^2 - 4(1)(-3)) ) / (2(1))
x = (-b +/- sqrt(b^2-4ac))/(2a)
x = (6 +/- sqrt(6^2 - 4(1)(-3)) ) / (2(1))
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