To find the roots of the quadratic equation 3x^2 + 999x - 50, we will use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a
In this case, a = 3, b = 999, and c = -50.
Plugging these values into the formula:
x = (-(999) ± √((999)^2 - 4(3)(-50))) / 2(3)
x = (-999 ± √(998001 + 600)) / 6
x = (-999 ± √998601) / 6
x = (-999 ± 999.3) / 6
Therefore, the two roots of the quadratic equation 3x^2 + 999x - 50 are:
x = (-999 + 999.3) / 6 ≈ 0.05
x = (-999 - 999.3) / 6 ≈ -333.05
So the roots are approximately x ≈ 0.05 and x ≈ -333.05.
use the quadratic formula
3x^2+999x-50
1 answer