Question

Use the quadratic formula to slove the equation.
x^2-x=-7
This is what I have got so far and I do not think this is right:
x=1(-1)±√-1^2-4(1)(7)/2(1)
x=1±√1-4(7)/2
x=1±√-21/2
x=1±-21/2
and here I am lost!

Use rational exponents to simplify. √(5&x^10 )

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Divide and simplify. (3y-6)/14÷(y-2)/4y

Answer 1

change it to the standard form first

x^2 - x + 7 = 0
a=1, b=-1, c = 7

x = (1 ± √(1 - 4(1)(7))/2
= (1 ± √-27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as
x = (1 ± 3√3 i)/2

Answer 2

x^2-x+7=0


x= (1+-sqrt(1-28))/2=1/2 +- 1/2 sqrt-21

and sqrt-21= isqrt21

2) I don't understand the others.

Answer 3

Okay so do I write the answer as the solution set is:(1 } 3ã3 i)/2 , 0