Question
a bullet of mass 0.01kg is fired into a sandbag of mass 0.49kg handing from atree.the sandbag with the bullet embedded into it swing away at 10m/s find: a.the momentum after collision b.the momentum before the collision c.the velocity of the bullet
Answers
bobpursley
a. (.01+.49)10
b. same as a.
c. .01V=momentum in b.
b. same as a.
c. .01V=momentum in b.
Birhan abate
A=5 b=5 c= 0.01
Leul
A)Pf=(m1+m2)v
= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05
= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05
Anonymous
by what angle velocity will be 0.05m/s?
Anonymous
0.01v=5kgm/s is 500m/s
Yanit
I hate it u didn't even give me good answers just stupid ones and no explanation
rose'e
you're good but can you make it brief abt the sol
anyway thank you for your help
anyway thank you for your help
Fikru
A.5
B.5
C.,500
B.5
C.,500
Fikru
A.5
B.5
C.500
B.5
C.500
Raol
A.5
B.5
C.500
B.5
C.500
Kedir
Mohammed