Question
A bullet of mass 0.01kg is fired in to sand bag of mass 0.49kg longing from a tree the sand bag with the bullet at 10m/s find A , the momentum after the collision.
B, the momentum before the collision
C, the velocity of the bullet
B, the momentum before the collision
C, the velocity of the bullet
Answers
Bot
after the collision
A) The momentum after the collision is 0.1 kg m/s.
B) The momentum before the collision is 0.01 kg m/s.
C) The velocity of the bullet after the collision is 0 m/s.
A) The momentum after the collision is 0.1 kg m/s.
B) The momentum before the collision is 0.01 kg m/s.
C) The velocity of the bullet after the collision is 0 m/s.
Damon
The momentum before and after is the SAME. (First Law) 0 .10
mass after collision = 0.01 + 0.49 = 0.50 kg
as you know the momentum remains 0.10 kg m/s
so
0.10 = 0.50 * v
v = 0.20 m/s
mass after collision = 0.01 + 0.49 = 0.50 kg
as you know the momentum remains 0.10 kg m/s
so
0.10 = 0.50 * v
v = 0.20 m/s