Asked by Gadisa
A bullet of mass 0.01kg is fired into a sandbag of mass 0.49 kg hanging from a tree. Swings away at 10 m/s. Find
A) the momentum after the collision.
B) the momentum before the collision.
C) the velocity of the bullet.
A) the momentum after the collision.
B) the momentum before the collision.
C) the velocity of the bullet.
Answers
Answered by
Anonymous
(A and B) the momentum after is exactly the same as the momentum before
P = momentum = m v = (0.01 + 0.49) * 10 = 5 kg m/s
(C) 5 kg m/s = 0.01 kg u
u = 5 / 0.01 = 500 m/s
P = momentum = m v = (0.01 + 0.49) * 10 = 5 kg m/s
(C) 5 kg m/s = 0.01 kg u
u = 5 / 0.01 = 500 m/s
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