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A bullet of mass 0.01kg is fired into a sandbag of mass 0.49 kg hanging from a tree. Swings away at 10 m/s. Find
A) the momentum after the collision.
B) the momentum before the collision.
C) the velocity of the bullet.
3 years ago

Answers

Anonymous
(A and B) the momentum after is exactly the same as the momentum before
P = momentum = m v = (0.01 + 0.49) * 10 = 5 kg m/s

(C) 5 kg m/s = 0.01 kg u
u = 5 / 0.01 = 500 m/s
3 years ago

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