CuSO4.5H2O ==> CuSO4 + 5H2O
The question is asking how much CuSO4 is left if all of the H2O is driven off.
The easy way to do this is calculate % water in CuSO4.5H2O.
If 25 grams of copper(II) sulfate pentahydrate were heated until all water was removed, how much residue would remain?- Could someone help me understand this question? I don't understand it at all. Thanks
3 answers
Since there is 5H2O is about 36% of CUSO4 + 5H2O , would there be about 16 g of residue left over? Thanks
ABOUT, yes. It's about 64% CuSO4 so
0.64 x 25 = about 16.
0.64 x 25 = about 16.