Asked by Melissa

3.05 g of hydrated copper sulfate produce 1.94 g of anhydrous salt. Assuming complete removal of water of crystallisation, determine the formula of hydrated copper sulfate.
Answered by DrBob222
CuSO4.xH2O ==> CuSO4 + xH2O

g H2O = g hydrate - g salt = 1.11g
mols CuSO4 = grams/molar mass = ?
mols H2O = grams/molar mass = ?

Now find the ratio of mols H2O to mols of 1 mol CuSO4 and round to the nearest whole number.
Answered by irish
-0.01MOL OF CUSO4
-0.12MOL OF H20
:FORMULAR IS CUSO4[H20]12
Answered by Meeraa
where did you get the mass of water?
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