Asked by Ehis

How much work is needed to stop a 20g bullet moving with a speed of 150ms-1
Answered by Elena
W=ΔKE= mv²/2 =0.02•150²/2=…
Answered by martins
m-20g-0.02kg
v-150ms/1
k.e-1/2mv2
k.e-1/2*0.02*150*150
1/2 to decimal-
0.5*0.02*150*150
225joules
Answered by alfred
225j
Answered by adaran fogo
m=20g
v=150ms
1/2 to decimal
0.5*0.02*150*150=
150joules
Answered by Ekhator
Show the formula

Answered by Collins
How much work is needed to stop a 20kg bullet with a speed of 150 minutes
Answered by OLAWEPO ADESEWA
225j
Answered by Precious
W=f×s
W=20×150=3000joules
Answered by Lizzy Joshua
225j
Answered by Lizzy Joshua
667j
Answered by Precious
I don't know i am the one asking the question
Answered by Eniola
K.e+p.e
Answered by Akinwole alao
225J
Answered by Anonymous
225j
Answered by Eminem Henry
How much work is needed to stop a 20kg bullet with a speed of 150 minutesHow much work is needed to stop a 20kg bullet with a speed of 150 minutes.
K. E =1/2MV²
MASS= 20g =20/1000
=0.02kg
V = 150ms-¹
K. E = 0.02*150*150/2
=225j
Answered by Anonymous
A loaded sack of rice of total Mass 100kg falls down from the floor of a lorry owned by mis Nancy if the hight of the lorry is 2cm calculate the work done by gravity on the load (g=10m/s)

Answered by Anonymous
A loaded sack of rice of total Mass 10kg falls down from the floor of a lorry owned by mis Nancy if the hight of the lorry is 2m calculate the work done by gravity on the load (g=10m/s)
Answered by Yakubu
W= f x s
W= 20 x 150
=3000j.
Answered by Samuel Oti
Since the bullet is in motion =k.e.ke=1/2*m*v^2.first convert the 20g to its unit kg.divide 20 divide 1000 =0.02.1/2*0.2*150^2=225 joules
Answered by Santos
W=f×s
=20×150
=3000
There are no AI answers yet. The ability to request AI answers is coming soon!